1st expression
![]()
From the following general rule in 0113
When a3=b3=1 together with b2=b2-1,
![]()
while the last negative sign remains unchanged.
2nd expression in the same way
![]()
From Rule 2 of signs(down->front and next)
![]()
We can say that
![]()
From the following same general rule in 0113
When a3=1 and b3=-1 together with b2=b2+1,
![]()
Applying Rule 2 of signs again(down->front and next)
![]()
Finally, we have
![]()