Dynamic programming and Bellman Equation

 

We consider the following optimization problem

 

          subject to

 

We convert it into the following Bellman equation

 

      at time t

 

We guess .

 

Then we get

 

 

Its first order condition with respect to kt+1 is

 

(F.O.C)

 

because there is no term involved in kt+1 on the left hand side.

 

From the function of function rule,

 

The derivative of  with respect to kt+1 is  times –1 inside.

 

That is,

 

 

Substituting it back to Bellman equation in terms of guess form,

 

 

Arranging the same kinds of terms, we compare the coefficients and get

 

and

 

That is

 

and

 

where we have all solved out. That guess is right.

 

Value function is

 


The phase (k,k’) can be expressed as

       from FOC

or simply