We consider the following special Bellman equation with Epstein-Zin preference
at time t
where
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and
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where
is random return
that is strictly positive.
Basically, we use the following two:
(1) The part
is a linear function of st.
(2) Envelope condition with respect to Wt
to simplify the problem.
We guess
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Then Bellman equation is going to be
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where
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FOC w.r.t. st is
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where
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by function of function rule many times.
Firstly, from envelope condition with respect to Wt, we have
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Thus
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It means that the first part factored out
is some positive when
.
Then we can say that
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since the part factored out is positive. That is
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Secondly, we set
and
where B is some
constant because
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or ![]()
where it is a linear function of st and we can set
for some constant B.
Now
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is set to be
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using this constant B.
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where let us define it as G for simplicity.
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So
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Plugging it into Bellman equation, we get
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Comparing the coefficients, we finally get
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Since both B and G are functions of A, all we have to do is solve this for A.
We have solved out and the guess is right.